# Factoring method for quadratic polynomials essay

Example 4 Factor each of the following. Check the factored form by multiplying. Since the product of two numbers is negative, I know that these numbers must have opposite signs.

The final answer should be the same. Here is the factored form of the polynomial.

Factor a Binomial Example 3. There are two methods for attacking these: If the polynomial is a binomial, check to see if it is the difference of squares, the difference of cubes, or the sum of cubes.

What we need to do is simply set each factor equal to zero, and solve each equation for x. This problem is similar to example 3. There are several significant things to notice: In the first set of parentheses, we include one factor of each cubed term and the sign will be the same as that of the original problem.

I can easily create a zero on the right side by subtracting both sides by In this lesson we summarize and apply the factoring methods presented in the previous sections.

This seems tedious, and indeed it can be if the numbers you are working with have a lot of factors, but in practice you usually only have to try a few combinations before you see what will work. This gets messy because all those coefficients will be mixed in with the middle term when you FOIL the binomials.

Here are all the possible ways to factor using only integers. We need to find two numbers that multiply product to give you —12 and add sum to give you —1. In this case 3 and 3 will be the correct pair of numbers.

In this example the 2x2 must come from x 2xand the constant term might come from either -1 3 or 1 All you really need to check is to see if the sum of the outer and inner multiplications will give you the correct middle term, since we already know that we will get the correct first and last terms.

Coefficient of x2 is not 1 A quadratic is more difficult to factor when the coefficient of the squared term is not 1, because that coefficient is mixed in with the other products from FOILing the two binomials.

Here is the factored form for this polynomial. We got the 5x by adding the 2x and the 3x when we collected like terms. List all the possible ways to get the coefficient of x2 which we call a by multiplying two numbers 2. The hard part is figuring out which combination will give the correct middle term.

Obviously, x2 factors into x xbut this is not a very interesting case. Multiply to give the constant term which we call c 2. List all the possible ways to get the constant term which we call c by multiplying two numbers 3. In that case, you can factor out that common factor.

Add to give the coefficient of x which we call b This rule works even if there are minus signs in the quadratic expression assuming that you remember how to add and multiply positive and negative numbers. However, there is another trick that we can use here to help us out.Factoring quadratics with the box method can be a bit confusing.

However, if you are confident with algebra and would like to try it, you can attempt factoring quadratics with the box method. You should use the simplified method for factoring quadratics if you are not as confident with algebra.

Read this essay on Factoring. Come browse our large digital warehouse of free sample essays. FACTORING polynomials Factoring polynomials is simply the reverse process of the special product formulas.

Thus, the reverse process of special product formulas will be used to factor polynomials.

I find the Quadratic Formula to be the. This is the easiest method of solving a quadratic equation as long as the binomial or trinomial is easily factorable. Otherwise, we will need other methods such as completing the square or using the quadratic formula. The following diagram illustrates the main approach to solving a.